What is the limit as x approaches infinity of 4^{-x} ?

The limit as x approaches infinity of 4^{-x} is 0

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limit as x approaches infinity of 4^{-x}

x \to \infty lim (4^{- x})

0

Solution steps

x \to \infty lim (4^{- x})

Apply exponent rules

= x \to \infty lim (e^{- x l n (4)})

Apply the Limit Chain Rule:

0

= 0

\frac{\partial}{\partial x} (\frac{1}{2 x})

\frac{d}{d t} (k t e^{3 t})

\frac{d}{d x} (\frac{2 x}{x - 1})

\frac{d ^{2}}{d x ^{2}} (\frac{3}{4 x ^{6}})

\int sin (a x) cos (b x) d x

What is the limit as x approaches infinity of 4^{-x} ?
The limit as x approaches infinity of 4^{-x} is 0