What is the tangent of 2x^2-13+1 ?

The tangent of 2x^2-13+1 is y=4a_{0}x-2a_{0}^2-12

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tangent of 2x^2-13+1

tangent of

2 x^{2} - 13 + 1

y = 4 a_{0} x - 2 a_{0}^{2} - 12

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 2 a_{0}^{2} - 12)

Find the slope of

y = 2 x^{2} - 13 + 1 : \frac{d y}{d x} = 4 x

Compute the slope of

y = 2 x^{2} - 13 + 1

x = a_{0} : m = 4 a_{0}

Find the line with slope m=

4 a_{0}

and passing through

(a_{0}, 2 a_{0}^{2} - 12) : y = 4 a_{0} x - 2 a_{0}^{2} - 12

y = 4 a_{0} x - 2 a_{0}^{2} - 12

\int_{0}^{\infty} e^{- 5 t} d t

f (x) = x (1 - x^{2})

y = (\frac{x ^{2} + 3}{x ^{2} - 3})^{8}

f (x) = \frac{7}{1 - x}

x^{2} x^{3} + 1

What is the tangent of 2x^2-13+1 ?
The tangent of 2x^2-13+1 is y=4a_{0}x-2a_{0}^2-12