What is the derivative of 1/(12x^3) ?

The derivative of 1/(12x^3) is -1/(4x^4)

What is the first derivative of 1/(12x^3) ?

The first derivative of 1/(12x^3) is -1/(4x^4)

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derivative of

\frac{1}{12 x ^{3}}

- \frac{1}{4 x ^{4}}

Solution steps

\frac{d}{d x} (\frac{1}{12 x ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{12} \frac{d}{d x} (\frac{1}{x ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{1}{12} \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{12} (- 3 x^{- 3 - 1})

Simplify

\frac{1}{12} (- 3 x^{- 3 - 1}) : - \frac{1}{4 x ^{4}}

= - \frac{1}{4 x ^{4}}

\int_{0}^{\infty} \frac{4}{x ^{2} + 4} d x

\frac{d}{d x} (tan (e^{x}))

n = 1 \sum \infty (- 1)^{n} n x^{n}

f (x) = \frac{8 x ^{2} + 6 x + 4}{x}

\frac{d y}{d t} = t 1 - y^{2}

What is the derivative of 1/(12x^3) ?
The derivative of 1/(12x^3) is -1/(4x^4)
What is the first derivative of 1/(12x^3) ?
The first derivative of 1/(12x^3) is -1/(4x^4)