What is the integral of f(1/2 \sqrt[3]{x}) ?

The integral of f(1/2 \sqrt[3]{x}) is (3fx^{4/3})/8+C

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integral of f(1/2 \sqrt[3]{x})

\frac{3 f x ^{\frac{4}{3}}}{8} + C

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

Simplify

\frac{1}{2} f : \frac{f}{2}

Apply the Power Rule

: \frac{3}{4} x^{\frac{4}{3}}

= \frac{f}{2} \cdot \frac{3}{4} x^{\frac{4}{3}}

Simplify

\frac{f}{2} \cdot \frac{3}{4} x^{\frac{4}{3}} : \frac{3 f x ^{\frac{4}{3}}}{8}

= \frac{3 f x ^{\frac{4}{3}}}{8}

Add a constant to the solution

= \frac{3 f x ^{\frac{4}{3}}}{8} + C

\frac{\partial}{\partial x} (4 x^{3} - 4 yz)

\frac{\partial}{\partial x} (e^{y} - y e^{x})

(a - 1) + 1

y^{^{'}} + \frac{2 y}{t + 2} = (t + 2)^{5}, y (0) = 5

\frac{1}{s ^{3} + 4 s}

What is the integral of f(1/2 \sqrt[3]{x}) ?
The integral of f(1/2 \sqrt[3]{x}) is (3fx^{4/3})/8+C