What is the solution for 6=(dx)/(dt)+(3x)/(20) ?

The solution for 6=(dx)/(dt)+(3x)/(20) is x=(e^{(-3t-c_{1})/(20)})/3+40

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6=(dx)/(dt)+(3x)/(20)

6 = \frac{d x}{d t} + \frac{3 x}{20}

x = \frac{e ^{\frac{- 3 t - c _{1}}{20}}}{3} + 40

Solution steps

6 = \frac{d x}{d t} + \frac{3 x}{20}

Solve separable ODE:

x = \frac{e ^{\frac{- 3 t - c _{1}}{20}}}{3} + 40

x = \frac{e ^{\frac{- 3 t - c _{1}}{20}}}{3} + 40

f (y) = 2 y^{2}

\int \frac{15}{2 x - 4} d x

\int \frac{5 x ^{2} + 2 x + 2}{x ^{3} - 1} d x

x \to \infty lim (- x e^{- x})

y^{^{''}} + 2 y^{^{'}} + y = x^{2}, y (0) = 1, y^{^{'}} (0) = 2

What is the solution for 6=(dx)/(dt)+(3x)/(20) ?
The solution for 6=(dx)/(dt)+(3x)/(20) is x=(e^{(-3t-c_{1})/(20)})/3+40