What is the solution for y^{''}-y=0,y(0)=3,y^'(0)=-1 ?

The solution for y^{''}-y=0,y(0)=3,y^'(0)=-1 is y=e^t+2e^{-t}

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y^{''}-y=0,y(0)=3,y^'(0)=-1

y^{^{''}} - y = 0, y (0) = 3, y^{^{'}} (0) = - 1

y = e^{t} + 2 e^{- t}

Solution steps

y^{''} (t) - y = 0

Solve linear ODE:

y = e^{t} + 2 e^{- t}

y = e^{t} + 2 e^{- t}

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What is the solution for y^{''}-y=0,y(0)=3,y^'(0)=-1 ?
The solution for y^{''}-y=0,y(0)=3,y^'(0)=-1 is y=e^t+2e^{-t}