What is the derivative of-2x^4+7xe^x ?

The derivative of-2x^4+7xe^x is -8x^3+7(e^x+e^xx)

What is the first derivative of-2x^4+7xe^x ?

The first derivative of-2x^4+7xe^x is -8x^3+7(e^x+e^xx)

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derivative of

- 2 x^{4} + 7 x e^{x}

- 8 x^{3} + 7 (e^{x} + e^{x} x)

Solution steps

\frac{d}{d x} (- 2 x^{4} + 7 x e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (2 x^{4}) + \frac{d}{d x} (7 x e^{x})

\frac{d}{d x} (2 x^{4}) = 8 x^{3}

\frac{d}{d x} (7 x e^{x}) = 7 (e^{x} + e^{x} x)

= - 8 x^{3} + 7 (e^{x} + e^{x} x)

\int (b - ∣ x ∣)^{2} d x

f (x) = - 8 x^{2} - 7, at x = 1

\int ln (5 x + 8) d x

\frac{x ^{2} \cdot cos ( x )}{( 2 x + 1 ) ^{3}}

\int \frac{5 x + 2}{3 x 1 - 3 x} d x

What is the derivative of-2x^4+7xe^x ?
The derivative of-2x^4+7xe^x is -8x^3+7(e^x+e^xx)
What is the first derivative of-2x^4+7xe^x ?
The first derivative of-2x^4+7xe^x is -8x^3+7(e^x+e^xx)