What is the integral of ((inx)^2)/x ?

The integral of ((inx)^2)/x is i^2n^2x^2-(i^2n^2x^2)/2+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of ((inx)^2)/x

\int \frac{( in x ) ^{2}}{x} d x

i^{2} n^{2} x^{2} - \frac{i ^{2} n ^{2} x ^{2}}{2} + C

Solution steps

\int \frac{( in x ) ^{2}}{x} d x

Apply Integration By Parts

: i^{2} n^{2} x^{2} - \int i^{2} n^{2} x d x

= i^{2} n^{2} x^{2} - \int i^{2} n^{2} x d x

\int i^{2} n^{2} x d x = \frac{i ^{2} n ^{2} x ^{2}}{2}

= i^{2} n^{2} x^{2} - \frac{i ^{2} n ^{2} x ^{2}}{2}

Add a constant to the solution

= i^{2} n^{2} x^{2} - \frac{i ^{2} n ^{2} x ^{2}}{2} + C

n = 1 \sum \infty \frac{2}{2 n - 1}

\frac{d}{d x} (\frac{1 - 3 x ^{2}}{1 - 2 x})

\frac{d}{d x} (9 x + 5)

x \to 5 - lim (\frac{1}{( x - 5 ) ^{2}})

10

What is the integral of ((inx)^2)/x ?
The integral of ((inx)^2)/x is i^2n^2x^2-(i^2n^2x^2)/2+C