What is the derivative of ln(1-7x) ?

The derivative of ln(1-7x) is -7/(1-7x)

What is the first derivative of ln(1-7x) ?

The first derivative of ln(1-7x) is -7/(1-7x)

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derivative of

ln (1 - 7 x)

- \frac{7}{1 - 7 x}

Solution steps

\frac{d}{d x} (ln (1 - 7 x))

Apply the chain rule:

\frac{1}{1 - 7 x} \frac{d}{d x} (1 - 7 x)

= \frac{1}{1 - 7 x} \frac{d}{d x} (1 - 7 x)

\frac{d}{d x} (1 - 7 x) = - 7

= \frac{1}{1 - 7 x} (- 7)

Simplify

\frac{1}{1 - 7 x} (- 7) : - \frac{7}{1 - 7 x}

= - \frac{7}{1 - 7 x}

\frac{d}{d x} (ln (1 + sin (2 x)))

\int \frac{x ^{3}}{x ^{3} - 7 x + 6} d x

\frac{\partial}{\partial y} (sin (3 x + 4 y))

\int \frac{cos ( t )}{1 + sin ( t )} d t

\frac{\partial}{\partial x} (x^{2} ln (x))

What is the derivative of ln(1-7x) ?
The derivative of ln(1-7x) is -7/(1-7x)
What is the first derivative of ln(1-7x) ?
The first derivative of ln(1-7x) is -7/(1-7x)