What is the tangent of y=2x^4-16x^2+9,\at x=-4 ?

The tangent of y=2x^4-16x^2+9,\at x=-4 is y=-384x-1271

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tangent of y=2x^4-16x^2+9,\at x=-4

tangent of

y = 2 x^{4} - 16 x^{2} + 9, at x = - 4

y = - 384 x - 1271

Solution steps

Find the tangent point:

(- 4, 265)

Find the slope of

y = 2 x^{4} - 16 x^{2} + 9 : \frac{d y}{d x} = 8 x^{3} - 32 x

Compute the slope of

y = 2 x^{4} - 16 x^{2} + 9

x = - 4 : m = - 384

Find the line with slope m=

- 384

and passing through

(- 4, 265) : y = - 384 x - 1271

y = - 384 x - 1271

y = \frac{2}{x}, (5, \frac{2}{5})

\int - 2 x^{- 3} d x

y^{2} = 2 x, x = 2 y

x^{2} y^{^{''}} + x y^{^{'}} - 4 y = 0

\frac{d}{d x} (cos (x) + cot (x) + csc (x) + 3 e^{x})

What is the tangent of y=2x^4-16x^2+9,\at x=-4 ?
The tangent of y=2x^4-16x^2+9,\at x=-4 is y=-384x-1271