What is the integral from 1 to sqrt(3 of) 1/(1+x^2) ?

The integral from 1 to sqrt(3 of) 1/(1+x^2) is pi/(12)

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integral from 1 to sqrt(3 of) 1/(1+x^2)

\int_{1}^{3} \frac{1}{1 + x ^{2}} d x

\frac{π}{12}

Decimal Notation

0.26179 \dots

Solution steps

\int_{1}^{3} \frac{1}{1 + x ^{2}} d x

Use the common integral:

\int \frac{1}{1 + x ^{2}} d x = arctan (x)

= [arctan (x)]_{1}^{3}

Compute the boundaries:

\frac{π}{12}

= \frac{π}{12}

arctan (3 x^{2} - 1)

7 y^{^{''}} + y^{^{'}} = 0

n = 1 \sum \infty \frac{9}{n ^{2} + 1}

\int_{1}^{16} \frac{1}{10 + x} d x

x \to 1 + lim (\frac{3 + x}{x ^{2} - 1})

What is the integral from 1 to sqrt(3 of) 1/(1+x^2) ?
The integral from 1 to sqrt(3 of) 1/(1+x^2) is pi/(12)