What is the derivative of x^5+37x ?

The derivative of x^5+37x is 5x^4+37

What is the first derivative of x^5+37x ?

The first derivative of x^5+37x is 5x^4+37

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\frac{d}{d x} (x^{5} + 37 x)

5 x^{4} + 37

Solution steps

\frac{d}{d x} (x^{5} + 37 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{5}) + \frac{d}{d x} (37 x)

\frac{d}{d x} (x^{5}) = 5 x^{4}

\frac{d}{d x} (37 x) = 37

= 5 x^{4} + 37

x \to 0 lim (\frac{1}{1 - cos ( x )})

\int e^{- x^{2} + 3 x} d x

e^{- 5 t}

\frac{d y}{d x} = 10 x

\int \frac{1}{csc ^{4} ( 3 t ) sec ^{2} ( 3 t )} d t

What is the derivative of x^5+37x ?
The derivative of x^5+37x is 5x^4+37
What is the first derivative of x^5+37x ?
The first derivative of x^5+37x is 5x^4+37