What is the derivative of tan(x+x^4) ?

The derivative of tan(x+x^4) is sec^2(x)+4x^3

What is the first derivative of tan(x+x^4) ?

The first derivative of tan(x+x^4) is sec^2(x)+4x^3

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\frac{d}{d x} (tan (x) + x^{4})

sec^{2} (x) + 4 x^{3}

Solution steps

\frac{d}{d x} (tan (x) + x^{4})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (tan (x)) + \frac{d}{d x} (x^{4})

\frac{d}{d x} (tan (x)) = sec^{2} (x)

\frac{d}{d x} (x^{4}) = 4 x^{3}

= sec^{2} (x) + 4 x^{3}

\int arcsin (x) d x

y^{^{''}} - 2 y^{^{'}} + 26 y = 0, y (0) = 2, y^{^{'}} (0) = 5

\frac{\partial}{\partial x} (2 x ln (x^{2} y))

- \frac{2}{s ^{2}}

\int 5 x lo g_{10} (3 - x) d x

What is the derivative of tan(x+x^4) ?
The derivative of tan(x+x^4) is sec^2(x)+4x^3
What is the first derivative of tan(x+x^4) ?
The first derivative of tan(x+x^4) is sec^2(x)+4x^3