What is the integral from-1 to 1 of 1/(x^5) ?

The integral from-1 to 1 of 1/(x^5) is diverges

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integral from-1 to 1 of 1/(x^5)

\int_{- 1}^{1} \frac{1}{x ^{5}} d x

diverges

Solution steps

\int_{- 1}^{1} \frac{1}{x ^{5}} d x

Find undefined (singularity) points:

x = 0

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{- 1}^{0} \frac{1}{x ^{5}} d x + \int_{0}^{1} \frac{1}{x ^{5}} d x

\int_{- 1}^{0} \frac{1}{x ^{5}} d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

\frac{\partial}{\partial x} (7 e^{x} \cdot sin (y))

n = 1 \sum \infty \frac{1}{2 n ln ( n )}

\frac{d}{d x} (\frac{4 x ^{2} + 4 x + 2}{x})

\int_{1}^{3} 2 x e^{- 4 x} d x

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What is the integral from-1 to 1 of 1/(x^5) ?
The integral from-1 to 1 of 1/(x^5) is diverges