What is the limit as x approaches 0+of x^{-2} ?

The limit as x approaches 0+of x^{-2} is infinity

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limit as x approaches 0+of x^{-2}

x \to 0 + lim (x^{- 2})

\infty

Solution steps

x \to 0 + lim (x^{- 2})

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= x \to 0 + lim (\frac{1}{x ^{2}})

For

x

approaching

0

from the right

, x > 0 \Rightarrow x^{2} > 0

The denominator is a positive quantity approaching 0 from the right

= \infty

x \to 2 lim (ln ∣ 2 - x ∣)

\int 5 x^{2} e^{x^{3}} d x

\frac{d}{d x} ((2 x - 3)^{5} (x^{2} + 4 x)^{6})

\int tan^{4} (\frac{x}{3}) d x

\int_{1}^{2} \frac{x}{x ^{2} - 1} d x

What is the limit as x approaches 0+of x^{-2} ?
The limit as x approaches 0+of x^{-2} is infinity