What is the tangent of f(x)= 6/x ,\at x=-2 ?

The tangent of f(x)= 6/x ,\at x=-2 is y=-3/2 x-6

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tangent of f(x)= 6/x ,\at x=-2

tangent of

f (x) = \frac{6}{x}, at x = - 2

y = - \frac{3}{2} x - 6

Solution steps

Find the tangent point:

(- 2, - 3)

Find the slope of

f (x) = \frac{6}{x} : \frac{df ( x )}{d x} = - \frac{6}{x ^{2}}

Compute the slope of

f (x) = \frac{6}{x}

x = - 2 : m = - \frac{3}{2}

Find the line with slope m=

- \frac{3}{2}

and passing through

(- 2, - 3) : y = - \frac{3}{2} x - 6

y = - \frac{3}{2} x - 6

(7 x + 1)^{2}

x^{2} + 2 x, 2 x + 1

\frac{d}{d x} (25)

\frac{d}{d x} (\frac{tan ( 2 x )}{1 - cot ( 2 x )})

\int \frac{2 x + 3}{( x ^{2} + 3 x ) ^{2}} d x

What is the tangent of f(x)= 6/x ,\at x=-2 ?
The tangent of f(x)= 6/x ,\at x=-2 is y=-3/2 x-6