What is the derivative of t-t^{-1} ?

The derivative of t-t^{-1} is 1+1/(t^2)

What is the first derivative of t-t^{-1} ?

The first derivative of t-t^{-1} is 1+1/(t^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

t - t^{- 1}

1 + \frac{1}{t ^{2}}

Solution steps

\frac{d}{d t} (t - t^{- 1})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d t}{d t} - \frac{d}{d t} (t^{- 1})

\frac{d t}{d t} = 1

\frac{d}{d t} (t^{- 1}) = - \frac{1}{t ^{2}}

= 1 - (- \frac{1}{t ^{2}})

Simplify

= 1 + \frac{1}{t ^{2}}

\frac{\partial}{\partial x} (x + 2^{\frac{1}{x}})

y^{^{''}} + 6 y^{^{'}} + 8 y = x^{2} e^{- x}

\frac{\partial}{\partial x} (7 e^{x^{2} l n (y)})

\frac{d}{d x} (ln (x - y^{2}))

\int \frac{7}{x ^{2} x ^{2} + 9} d x

What is the derivative of t-t^{-1} ?
The derivative of t-t^{-1} is 1+1/(t^2)
What is the first derivative of t-t^{-1} ?
The first derivative of t-t^{-1} is 1+1/(t^2)