What is the solution for 3xydy=(y^2-x^2)dx ?

The solution for 3xydy=(y^2-x^2)dx is y=sqrt(-(x^2)/2+c_{1)x^{2/3}},y=-sqrt(-(x^2)/2+c_{1)x^{2/3}}

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3xydy=(y^2-x^2)dx

3 x y d y = (y^{2} - x^{2}) d x

y = - \frac{x ^{2}}{2} + c_{1} x^{\frac{2}{3}}, y = - - \frac{x ^{2}}{2} + c_{1} x^{\frac{2}{3}}

Solution steps

3 x y d y = (y^{2} - x^{2}) d x

Solve Bernoulli ODE:

y = - \frac{x ^{2}}{2} + c_{1} x^{\frac{2}{3}}, y = - - \frac{x ^{2}}{2} + c_{1} x^{\frac{2}{3}}

y = - \frac{x ^{2}}{2} + c_{1} x^{\frac{2}{3}}, y = - - \frac{x ^{2}}{2} + c_{1} x^{\frac{2}{3}}

\int \frac{4}{x} - \frac{16}{x ^{2}} d x

f (x) = (4 x - 1) cos (x)

f (x) = 2^{3} e^{2}

h \to + 0 lim (- 2 x - h)

\int (\frac{x + 1}{x ^{2} + 2 x}) d x

What is the solution for 3xydy=(y^2-x^2)dx ?
The solution for 3xydy=(y^2-x^2)dx is y=sqrt(-(x^2)/2+c_{1)x^{2/3}},y=-sqrt(-(x^2)/2+c_{1)x^{2/3}}