What is the derivative of f(x)=8e^x+4/(\sqrt[3]{x)} ?

The derivative of f(x)=8e^x+4/(\sqrt[3]{x)} is 8e^x-4/(3x^{4/3)}

What is the first derivative of f(x)=8e^x+4/(\sqrt[3]{x)} ?

The first derivative of f(x)=8e^x+4/(\sqrt[3]{x)} is 8e^x-4/(3x^{4/3)}

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derivative of

8 e^{x} - \frac{4}{3 x ^{\frac{4}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (8 e^{x}) = 8 e^{x}

= 8 e^{x} - \frac{4}{3 x ^{\frac{4}{3}}}

y = \frac{1}{x - 5}, at x = 8

\frac{d}{d x} (cot (1 - 2 x^{2}))

\int \frac{sin ( t )}{cos ( t )} d t

x \to 2 lim (2 x^{2} - 2)

7 cos (9 x), 7 - 7 cos (9 x)

What is the derivative of f(x)=8e^x+4/(\sqrt[3]{x)} ?
The derivative of f(x)=8e^x+4/(\sqrt[3]{x)} is 8e^x-4/(3x^{4/3)}
What is the first derivative of f(x)=8e^x+4/(\sqrt[3]{x)} ?
The first derivative of f(x)=8e^x+4/(\sqrt[3]{x)} is 8e^x-4/(3x^{4/3)}