What is the tangent of f(x)=2x-2sqrt(x) ?

The tangent of f(x)=2x-2sqrt(x) is y=(2-1/(sqrt(a_{0))})x-sqrt(a_{0)}

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tangent of f(x)=2x-2sqrt(x)

tangent of

f (x) = 2 x - 2 x

y = (2 - \frac{1}{a _{0}}) x - a_{0}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 2 a_{0} - 2 a_{0})

Find the slope of

f (x) = 2 x - 2 x : \frac{df ( x )}{d x} = 2 - \frac{1}{x}

Compute the slope of

f (x) = 2 x - 2 x

x = a_{0} : m = 2 - \frac{1}{a _{0}}

Find the line with slope m=

2 - \frac{1}{a _{0}}

and passing through

(a_{0}, 2 a_{0} - 2 a_{0}) : y = (2 - \frac{1}{a _{0}}) x - a_{0}

y = (2 - \frac{1}{a _{0}}) x - a_{0}

\int sec^{5} (5 x) d x

\frac{\partial}{\partial x} (7 x y e^{- x^{2} - y^{2}})

\int \frac{1}{49 e ^{- 3 x} + e ^{3 x}} d x

x^{5} (3 + 8 x)^{7}

\int_{- 2}^{1} x^{2} d x

What is the tangent of f(x)=2x-2sqrt(x) ?
The tangent of f(x)=2x-2sqrt(x) is y=(2-1/(sqrt(a_{0))})x-sqrt(a_{0)}