What is the solution for y^'=(0.04*4)-y/(1840)4 ?

The solution for y^'=(0.04*4)-y/(1840)4 is y=-0.25e^{(-t-c_{1})/(460)}+73.6

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y^'=(0.04*4)-y/(1840)4

y^{^{'}} = (0.04 \cdot 4) - \frac{y}{1840} 4

y = - 0.25 e^{\frac{- t - c _{1}}{460}} + 73.6

Solution steps

y^{'} (t) = (0.04 \cdot 4) - \frac{y}{1840} 4

Solve separable ODE:

y = - 0.25 e^{\frac{- t - c _{1}}{460}} + 73.6

y = - 0.25 e^{\frac{- t - c _{1}}{460}} + 73.6

x \to - 1 lim (\frac{1 - x}{x + 1})

\frac{\partial}{\partial y} (sin (x^{3} + y^{2}))

\frac{d}{d x} (\frac{3 x + 1}{x + 1})

\frac{2}{s ^{2} - 2 s + 9}

y^{^{''}} + 2 y^{^{'}} + y = x^{- 4} e^{- x}

What is the solution for y^'=(0.04*4)-y/(1840)4 ?
The solution for y^'=(0.04*4)-y/(1840)4 is y=-0.25e^{(-t-c_{1})/(460)}+73.6