What is the integral from 0 to 7 of k(7-x) ?

The integral from 0 to 7 of k(7-x) is (7-x) 49/2

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integral from 0 to 7 of k(7-x)

\int_{0}^{7} k (7 - x)

(7 - x) \frac{49}{2}

Solution steps

\int_{0}^{7} k (7 - x) d k

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= (7 - x) \cdot \int_{0}^{7} k d k

\int_{0}^{7} k d k = \frac{49}{2}

= (7 - x) \frac{49}{2}

t \to + 0 lim (18 (1.15)^{t})

x \to 7 + lim (\frac{9 x}{x - 7})

\int 2 x + 3 e^{x} d x

x^{2} y^{^{''}} - x y^{^{'}} + y = ln (x)

f^{^{'}} (x) = 6 x, f (0) = 8

What is the integral from 0 to 7 of k(7-x) ?
The integral from 0 to 7 of k(7-x) is (7-x) 49/2