What is the solution for (d^2y)/(dt^2)-15(dy)/(dt)+50y=0 ?

The solution for (d^2y)/(dt^2)-15(dy)/(dt)+50y=0 is y=c_{1}e^{10t}+c_{2}e^{5t}

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(d^2y)/(dt^2)-15(dy)/(dt)+50y=0

\frac{d ^{2} y}{d t ^{2}} - 15 \frac{d y}{d t} + 50 y = 0

y = c_{1} e^{10 t} + c_{2} e^{5 t}

Solution steps

\frac{d ^{2} y}{d t ^{2}} - 15 \frac{d y}{d t} + 50 y = 0

Solve linear ODE:

y = c_{1} e^{10 t} + c_{2} e^{5 t}

y = c_{1} e^{10 t} + c_{2} e^{5 t}

\frac{\partial}{\partial x} (9 e^{x y})

\frac{1}{2} x^{2}, - x^{2} + 6

y = x^{2} + 1, y = x + 3, (- 1, 2)

\frac{1}{s ( s + 1 )}

\frac{d}{d x} (c cos (t) + t^{2} sin (t))

What is the solution for (d^2y)/(dt^2)-15(dy)/(dt)+50y=0 ?
The solution for (d^2y)/(dt^2)-15(dy)/(dt)+50y=0 is y=c_{1}e^{10t}+c_{2}e^{5t}