What is the derivative of 6sin(θ) ?

The derivative of 6sin(θ) is 6cos(θ)

What is the first derivative of 6sin(θ) ?

The first derivative of 6sin(θ) is 6cos(θ)

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derivative of

6 sin (θ)

6 cos (θ)

Solution steps

\frac{d}{d θ} (6 sin (θ))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d θ} (sin (θ))

Apply the common derivative:

\frac{d}{d θ} (sin (θ)) = cos (θ)

= 6 cos (θ)

32 y^{^{''}} - 4 y^{^{'}} - 21 y = 0

\frac{d}{d x} (cos (x^{2}) 2 x)

f (x) = 4 x - x^{2}, (1, 3)

\int - (1 - ln (x)) d x

\int \frac{x}{3} d x

What is the derivative of 6sin(θ) ?
The derivative of 6sin(θ) is 6cos(θ)
What is the first derivative of 6sin(θ) ?
The first derivative of 6sin(θ) is 6cos(θ)