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Popular >

d/(d{z)}({x}{y}e^{({x}^2+{z}^2-5)})

Solution

\frac{d}{d z} (x y e^{(x^{2} + z^{2} - 5)})

Solution

x y e^{x^{2} + z^{2} - 5} \cdot 2 z

Solution steps

\frac{d}{d z} (x y e^{(x^{2} + z^{2} - 5)})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x y \frac{d}{d z} (e^{x^{2} + z^{2} - 5})

Apply the chain rule:

e^{x^{2} + z^{2} - 5} \frac{d}{d z} (x^{2} + z^{2} - 5)

= e^{x^{2} + z^{2} - 5} \frac{d}{d z} (x^{2} + z^{2} - 5)

\frac{d}{d z} (x^{2} + z^{2} - 5) = 2 z

= x y e^{x^{2} + z^{2} - 5} \cdot 2 z

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\frac{d}{d x} (e^{- \frac{4}{x}})

y^'=(6x^4+y^4)/(xy^3)

y^{^{'}} = \frac{6 x ^{4} + y ^{4}}{x y ^{3}}

integral of (7x^2)/(5-x^6)

\int \frac{7 x ^{2}}{5 - x ^{6}} d x

Frequently Asked Questions (FAQ)

What is the d/(d{z)}({x}{y}e^{({x}^2+{z}^2-5)}) ?
The d/(d{z)}({x}{y}e^{({x}^2+{z}^2-5)}) is {x}{y}e^{{x}^2+{z}^2-5}*2{z}
What is the first d/(d{z)}({x}{y}e^{({x}^2+{z}^2-5)}) ?
The first d/(d{z)}({x}{y}e^{({x}^2+{z}^2-5)}) is {x}{y}e^{{x}^2+{z}^2-5}*2{z}