What is area x=-3,x=1,y=e^x,y=1-e^x ?

The answer to area x=-3,x=1,y=e^x,y=1-e^x is 2e+2/(e^3)-2ln(2)

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area x=-3,x=1,y=e^x,y=1-e^x

area

x = - 3, x = 1, y = e^{x}, y = 1 - e^{x}

2 e + \frac{2}{e ^{3}} - 2 ln (2)

Decimal Notation

4.14984 \dots

Solution steps

Apply the area formula:

\int_{- 3}^{1} ∣ e^{x} - (1 - e^{x}) ∣ d x

Solve

\int_{- 3}^{1} ∣ e^{x} - (1 - e^{x}) ∣ d x : 2 e + \frac{2}{e ^{3}} - 2 ln (2)

The area is:

= 2 e + \frac{2}{e ^{3}} - 2 ln (2)

x y^{^{'}} + y = e^{x}, y (1) = 3

x \to 0 lim (x^{2} sin (x^{2}))

\frac{d}{d x} (x^{3} cos (3 x))

\int \frac{8 e ^{8 y}}{6 + e ^{8 y}} d y

\int \frac{2 x ^{2} - 3}{x ^{2}} d x

What is area x=-3,x=1,y=e^x,y=1-e^x ?
The answer to area x=-3,x=1,y=e^x,y=1-e^x is 2e+2/(e^3)-2ln(2)