What is the solution for 2x^2*(dy)/(dx)=piysin(pi/(2x)) ?

The solution for 2x^2*(dy)/(dx)=piysin(pi/(2x)) is y=e^{cos(pi/(2x))+c_{1}}

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2x^2*(dy)/(dx)=piysin(pi/(2x))

2 x^{2} \cdot \frac{d y}{d x} = π y sin (\frac{π}{2 x})

y = e^{c o s (\frac{π}{2 x}) + c_{1}}

Solution steps

2 x^{2} \cdot \frac{d y}{d x} = π y sin (\frac{π}{2 x})

Solve separable ODE:

y = e^{c o s (\frac{π}{2 x}) + c_{1}}

y = e^{c o s (\frac{π}{2 x}) + c_{1}}

x \to - 2 - lim (x^{4} + 5)

y = sin^{2} (x), y = 0

\frac{d}{d x} ((1 + 2 x^{2}) (x - x^{2}))

x \to \infty lim (x + 5)

\int \frac{y ^{2}}{x ^{2} + y ^{2}} d x

What is the solution for 2x^2*(dy)/(dx)=piysin(pi/(2x)) ?
The solution for 2x^2*(dy)/(dx)=piysin(pi/(2x)) is y=e^{cos(pi/(2x))+c_{1}}