What is the derivative of y=x^{8cos(x)} ?

The derivative of y=x^{8cos(x)} is 8x^{8cos(x)}(-sin(x)ln(x)+(cos(x))/x)

What is the first derivative of y=x^{8cos(x)} ?

The first derivative of y=x^{8cos(x)} is 8x^{8cos(x)}(-sin(x)ln(x)+(cos(x))/x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

y = x^{8 c o s (x)}

8 x^{8 c o s (x)} (- sin (x) ln (x) + \frac{cos ( x )}{x})

Solution steps

\frac{d}{d x} (x^{8 c o s (x)})

Apply exponent rule:

a^{b} = e^{b l n (a)}

x^{8 c o s (x)} = e^{8 c o s (x) l n (x)}

= \frac{d}{d x} (e^{8 c o s (x) l n (x)})

Apply the chain rule:

e^{8 c o s (x) l n (x)} \frac{d}{d x} (8 cos (x) ln (x))

= e^{8 c o s (x) l n (x)} \frac{d}{d x} (8 cos (x) ln (x))

\frac{d}{d x} (8 cos (x) ln (x)) = 8 (- sin (x) ln (x) + \frac{cos ( x )}{x})

= e^{8 c o s (x) l n (x)} \cdot 8 (- sin (x) ln (x) + \frac{cos ( x )}{x})

e^{8 c o s (x) l n (x)} = x^{8 c o s (x)}

= 8 x^{8 c o s (x)} (- sin (x) ln (x) + \frac{cos ( x )}{x})

\frac{d}{d x} (\frac{3 x}{1 + x ^{3}})

\frac{\partial}{\partial x} (5 x y e^{- x^{2} y})

\frac{\partial}{\partial x} (e^{- 2 x} cos (2 y))

\int e^{- θ} d θ

x \to \infty lim ((0)^{x})

What is the derivative of y=x^{8cos(x)} ?
The derivative of y=x^{8cos(x)} is 8x^{8cos(x)}(-sin(x)ln(x)+(cos(x))/x)
What is the first derivative of y=x^{8cos(x)} ?
The first derivative of y=x^{8cos(x)} is 8x^{8cos(x)}(-sin(x)ln(x)+(cos(x))/x)