What is the tangent of y=3x^3-3x,(1,0) ?

The tangent of y=3x^3-3x,(1,0) is y=6x-6

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tangent of y=3x^3-3x,(1,0)

tangent of

y = 3 x^{3} - 3 x, (1, 0)

y = 6 x - 6

Solution steps

Find the slope of

y = 3 x^{3} - 3 x : \frac{d y}{d x} = 9 x^{2} - 3

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 6

Find the line with slope m=

6

and passing through

(1, 0) : y = 6 x - 6

y = 6 x - 6

\frac{d y}{d x} = 2 y^{2} (x + 1)

\int cot (22 x) d x

\int \frac{1}{x ^{4} x ^{2} - 64} d x

\frac{\partial}{\partial x} (x^{l n (x)})

\int_{- 2}^{2} 2 x^{2} - 6 x + 14 d x

What is the tangent of y=3x^3-3x,(1,0) ?
The tangent of y=3x^3-3x,(1,0) is y=6x-6