What is the integral from 1 to 8 of (\sqrt[3]{x}) ?

The integral from 1 to 8 of (\sqrt[3]{x}) is 45/4

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integral from 1 to 8 of (\sqrt[3]{x})

\int_{1}^{8} (3 x) d x

\frac{45}{4}

Decimal

11.25

Solution steps

\int_{1}^{8} 3 x d x

Apply the Power Rule

: [\frac{3}{4} x^{\frac{4}{3}}]_{1}^{8}

= [\frac{3}{4} x^{\frac{4}{3}}]_{1}^{8}

Compute the boundaries:

\frac{45}{4}

= \frac{45}{4}

\frac{\partial}{\partial t} (1 + 2 t)

\int (x^{2} + x + 1) (e^{x}) d x

x y - 3 y^{2} = 2, (7, 2)

x \to 0 lim (3 x - 5)

\int (\frac{x + 2 x ^{2}}{x}) d x

What is the integral from 1 to 8 of (\sqrt[3]{x}) ?
The integral from 1 to 8 of (\sqrt[3]{x}) is 45/4