What is the tangent of f(x)= 4/x ,\at 9 4/9 ?

The tangent of f(x)= 4/x ,\at 9 4/9 is y=-4/(a_{0)^2}x+8/(a_{0)}

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tangent of f(x)= 4/x ,\at 9 4/9

tangent of

f (x) = \frac{4}{x}, at 9 \frac{4}{9}

y = - \frac{4}{a _{0}^{2}} x + \frac{8}{a _{0}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{4}{a _{0}})

Find the slope of

f (x) = \frac{4}{x} : \frac{df ( x )}{d x} = - \frac{4}{x ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{4}{a _{0}^{2}}

Find the line with slope m=

- \frac{4}{a _{0}^{2}}

and passing through

(a_{0}, \frac{4}{a _{0}}) : y = - \frac{4}{a _{0}^{2}} x + \frac{8}{a _{0}}

y = - \frac{4}{a _{0}^{2}} x + \frac{8}{a _{0}}

\int \frac{1}{2 x ^{2} + 2 x + 5} d x

\frac{\partial}{\partial x} (x^{\frac{3}{4}} \cdot y^{- 4})

\frac{d}{d x} (4 arcsin (x^{4}))

n = 0 \sum \infty \frac{6 ^{n}}{7 ^{n}}

x \to 0 + lim (ln (x) sin (x))

What is the tangent of f(x)= 4/x ,\at 9 4/9 ?
The tangent of f(x)= 4/x ,\at 9 4/9 is y=-4/(a_{0)^2}x+8/(a_{0)}