What is (d^2)/(dx^2)((4x)/(x^2+1)) ?

The answer to (d^2)/(dx^2)((4x)/(x^2+1)) is -(8x(-x^2+3))/((x^2+1)^3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(d^2)/(dx^2)((4x)/(x^2+1))

\frac{d ^{2}}{d x ^{2}} (\frac{4 x}{x ^{2} + 1})

- \frac{8 x ( - x ^{2} + 3 )}{( x ^{2} + 1 ) ^{3}}

Solution steps

\frac{d ^{2}}{d x ^{2}} (\frac{4 x}{x ^{2} + 1})

\frac{d}{d x} (\frac{4 x}{x ^{2} + 1}) = \frac{4 ( - x ^{2} + 1 )}{( x ^{2} + 1 ) ^{2}}

= \frac{d}{d x} (\frac{4 ( - x ^{2} + 1 )}{( x ^{2} + 1 ) ^{2}})

\frac{d}{d x} (\frac{4 ( - x ^{2} + 1 )}{( x ^{2} + 1 ) ^{2}}) = - \frac{8 x ( - x ^{2} + 3 )}{( x ^{2} + 1 ) ^{3}}

= - \frac{8 x ( - x ^{2} + 3 )}{( x ^{2} + 1 ) ^{3}}

\int x^{2020} d x

\frac{d}{d x} (ln (1 - \frac{2}{x}))

\int (25 - 0.2 x) d x

f (x) = \frac{1}{9 x}

\frac{\partial}{\partial x} (t^{4} e^{- x})

What is (d^2)/(dx^2)((4x)/(x^2+1)) ?
The answer to (d^2)/(dx^2)((4x)/(x^2+1)) is -(8x(-x^2+3))/((x^2+1)^3)