What is the integral from 0 to 2 of 1/2 y^2 ?

The integral from 0 to 2 of 1/2 y^2 is 4/3

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integral from 0 to 2 of 1/2 y^2

\int_{0}^{2} \frac{1}{2} y^{2} d y

\frac{4}{3}

Decimal

1.33333 \dots

Solution steps

\int_{0}^{2} \frac{1}{2} y^{2} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{0}^{2} y^{2} d y

Apply the Power Rule

: [\frac{y ^{3}}{3}]_{0}^{2}

= \frac{1}{2} [\frac{y ^{3}}{3}]_{0}^{2}

Compute the boundaries:

\frac{8}{3}

= \frac{1}{2} \cdot \frac{8}{3}

Simplify

= \frac{4}{3}

sin (\frac{t}{t + 9})

\int \frac{2 x + 1}{3 x ^{2} - 27} d x

\int \frac{1}{e ^{- x} + 1} d x

\int \frac{1}{2 + 7 y ^{2}} d y

e^{- 2 t}

What is the integral from 0 to 2 of 1/2 y^2 ?
The integral from 0 to 2 of 1/2 y^2 is 4/3