What is the solution for y^'+2x^5y=(x^5)/(y^2) ?

The solution for y^'+2x^5y=(x^5)/(y^2) is y=\sqrt[3]{(-e^{-x^6-c_{1}}+1)/2}

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y^'+2x^5y=(x^5)/(y^2)

y^{^{'}} + 2 x^{5} y = \frac{x ^{5}}{y ^{2}}

y = 3 \frac{- e ^{- x^{6} - c_{1}} + 1}{2}

Solution steps

y^{'} (x) + 2 x^{5} y = \frac{x ^{5}}{y ^{2}}

Solve separable ODE:

y = 3 \frac{- e ^{- x^{6} - c_{1}} + 1}{2}

y = 3 \frac{- e ^{- x^{6} - c_{1}} + 1}{2}

\frac{10 x}{- 3 y ^{2}}

x \to 0 + lim (\frac{ln ( x )}{x ^{3}})

\frac{x}{x + 2}

\int x^{\frac{5}{3}} ln (x) d x

f (x) = x^{2} + 11 x - 15, at x = 1

What is the solution for y^'+2x^5y=(x^5)/(y^2) ?
The solution for y^'+2x^5y=(x^5)/(y^2) is y=\sqrt[3]{(-e^{-x^6-c_{1}}+1)/2}