What is the integral of 4sec^2(x) ?

The integral of 4sec^2(x) is 4tan(x)+C

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integral of 4sec^2(x)

\int 4 sec^{2} (x) d x

4 tan (x) + C

Solution steps

\int 4 sec^{2} (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= 4 tan (x)

Add a constant to the solution

= 4 tan (x) + C

\frac{d}{d x} (x e)

\int \frac{8}{sec ( 2 x ) - 1} d x

\frac{\partial}{\partial x} (sin (x y) z^{2})

y = \frac{- 4 x}{x ^{2} + 1}, (0, 0)

x y^{^{'}} - 4 y = - 2 x