What is the solution for (dy)/(dx)=(y^2+2xy)/(x^2) ?

The solution for (dy)/(dx)=(y^2+2xy)/(x^2) is y=(x^2)/(-x+c_{1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=(y^2+2xy)/(x^2)

\frac{d y}{d x} = \frac{y ^{2} + 2 x y}{x ^{2}}

y = \frac{x ^{2}}{- x + c _{1}}

Solution steps

\frac{d y}{d x} = \frac{y ^{2} + 2 x y}{x ^{2}}

Solve Bernoulli ODE:

y = \frac{x ^{2}}{- x + c _{1}}

y = \frac{x ^{2}}{- x + c _{1}}

\int \frac{1 - 2 x}{x ( 1 - x )} d x

\frac{- 4 x}{x ^{2} + 1}

\frac{d}{d x} ((x - 4)^{2})

\int \frac{( 1 - x ) ^{3}}{x ^{3} x} d x

\frac{d}{d t} (e^{3 t} cos (2 t))

What is the solution for (dy)/(dx)=(y^2+2xy)/(x^2) ?
The solution for (dy)/(dx)=(y^2+2xy)/(x^2) is y=(x^2)/(-x+c_{1)}