What is the derivative of 1+9/25 y^4 ?

The derivative of 1+9/25 y^4 is (36y^3)/(25)

What is the first derivative of 1+9/25 y^4 ?

The first derivative of 1+9/25 y^4 is (36y^3)/(25)

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derivative of

1 + \frac{9}{25} y^{4}

\frac{36 y ^{3}}{25}

Solution steps

\frac{d}{d y} (1 + \frac{9}{25} y^{4})

Simplify

1 + \frac{9}{25} y^{4} : 1 + \frac{9 y ^{4}}{25}

= \frac{d}{d y} (1 + \frac{9 y ^{4}}{25})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d y} (1) + \frac{d}{d y} (\frac{9 y ^{4}}{25})

\frac{d}{d y} (1) = 0

\frac{d}{d y} (\frac{9 y ^{4}}{25}) = \frac{36 y ^{3}}{25}

= 0 + \frac{36 y ^{3}}{25}

Simplify

= \frac{36 y ^{3}}{25}

- 5 t

\frac{d}{d x} (arcsin (3 x^{4}))

(2, 8), (4, 6)

\frac{d y}{d x} = \frac{6 y ^{3}}{( 3 - 2 x ) ^{2}}, y (0) = - 1

\int \frac{t ^{2}}{2} d t

What is the derivative of 1+9/25 y^4 ?
The derivative of 1+9/25 y^4 is (36y^3)/(25)
What is the first derivative of 1+9/25 y^4 ?
The first derivative of 1+9/25 y^4 is (36y^3)/(25)