What is the derivative of 1/6 x^2-3x+15 ?

The derivative of 1/6 x^2-3x+15 is x/3-3

What is the first derivative of 1/6 x^2-3x+15 ?

The first derivative of 1/6 x^2-3x+15 is x/3-3

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derivative of

\frac{1}{6} x^{2} - 3 x + 15

\frac{x}{3} - 3

Solution steps

\frac{d}{d x} (\frac{1}{6} x^{2} - 3 x + 15)

Simplify

\frac{1}{6} x^{2} - 3 x + 15 : \frac{x ^{2}}{6} - 3 x + 15

= \frac{d}{d x} (\frac{x ^{2}}{6} - 3 x + 15)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{2}}{6}) - \frac{d}{d x} (3 x) + \frac{d}{d x} (15)

\frac{d}{d x} (\frac{x ^{2}}{6}) = \frac{x}{3}

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (15) = 0

= \frac{x}{3} - 3 + 0

Simplify

= \frac{x}{3} - 3

\int cos (y) cos (4 y) d y

2 x - x^{2}, - 3

\frac{d}{d x} (3 tan (x))

\int \frac{1}{( 1 - x ^{4} )} d x

\frac{d}{d x} (cos (x) sin (x))

What is the derivative of 1/6 x^2-3x+15 ?
The derivative of 1/6 x^2-3x+15 is x/3-3
What is the first derivative of 1/6 x^2-3x+15 ?
The first derivative of 1/6 x^2-3x+15 is x/3-3