What is the integral of s7^s ?

The integral of s7^s is (7^ss)/(ln(7))-(7^s)/(ln^2(7))+C

Popular >

integral of s7^s

\int s 7^{s} d s

\frac{7 ^{s} s}{ln ( 7 )} - \frac{7 ^{s}}{ln ^{2} ( 7 )} + C

Solution steps

\int s \cdot 7^{s} d s

Apply Integration By Parts

: \frac{7 ^{s} s}{ln ( 7 )} - \int \frac{7 ^{s}}{ln ( 7 )} d s

= \frac{7 ^{s} s}{ln ( 7 )} - \int \frac{7 ^{s}}{ln ( 7 )} d s

\int \frac{7 ^{s}}{ln ( 7 )} d s = \frac{7 ^{s}}{ln ^{2} ( 7 )}

= \frac{7 ^{s} s}{ln ( 7 )} - \frac{7 ^{s}}{ln ^{2} ( 7 )}

Add a constant to the solution

= \frac{7 ^{s} s}{ln ( 7 )} - \frac{7 ^{s}}{ln ^{2} ( 7 )} + C

\frac{\partial}{\partial x} (ln (x + 9 y + 4 z))

x \to 2 lim (5 x - 7)

\int \frac{x ^{4} + 1}{x ( x ^{2} + 2 ) ^{2}} d x

x \to π lim (ln ∣ cos (x) - 9 ∣)

- sec (\frac{π}{3}) + 2 sec^{3} (\frac{π}{3})

What is the integral of s7^s ?
The integral of s7^s is (7^ss)/(ln(7))-(7^s)/(ln^2(7))+C