What is the integral of 3csc(x)cot(x) ?

The integral of 3csc(x)cot(x) is -3csc(x)+C

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integral of 3csc(x)cot(x)

\int 3 csc (x) cot (x) d x

- 3 csc (x) + C

Solution steps

\int 3 csc (x) cot (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int csc (x) cot (x) d x

Apply u-substitution

: \int - 1 d u

= 3 \cdot \int - 1 d u

Integral of a constant:

\int a d x = a x

= 3 (- 1) u

Substitute back

u = csc (x)

= 3 (- 1) csc (x)

Simplify

= - 3 csc (x)

Add a constant to the solution

= - 3 csc (x) + C

\int \frac{x}{x ^{4} + 10} d x

\frac{x}{x - 1}

\frac{d}{d x} (x (1 - x)^{2})

lo g_{10} ((arcsin (x))^{2})

(- x^{3} + 4 x^{2} - 5 x)^{^{'}}

What is the integral of 3csc(x)cot(x) ?
The integral of 3csc(x)cot(x) is -3csc(x)+C