What is the tangent of y=8sin(pix-y),(1,0) ?

The tangent of y=8sin(pix-y),(1,0) is y=(8pi)/7 x-(8pi)/7

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tangent of y=8sin(pix-y),(1,0)

tangent of

y = 8 sin (π x - y), (1, 0)

y = \frac{8 π}{7} x - \frac{8 π}{7}

Solution steps

Find the slope of

y = 8 sin (π x - y) : \frac{d y}{d x} = \frac{8 π cos ( π x - y )}{1 + 8 cos ( - y + π x )}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{8 π}{7}

Find the line with slope m=

\frac{8 π}{7}

and passing through

(1, 0) : y = \frac{8 π}{7} x - \frac{8 π}{7}

y = \frac{8 π}{7} x - \frac{8 π}{7}

\frac{d}{d x} ((3 sin (x) + x)^{3})

x \to 2 lim (\frac{3 - 4 x + 1}{( x ^{2} - 2 x )})

sin (t + \frac{11 π}{2})

x \to 1 lim (\frac{3 x}{2 x + 2})

y^{^{'}} = \frac{6 x ^{5} y}{ln ( y )}

What is the tangent of y=8sin(pix-y),(1,0) ?
The tangent of y=8sin(pix-y),(1,0) is y=(8pi)/7 x-(8pi)/7