What is the tangent of e^x,\at x=ln(7) ?

The tangent of e^x,\at x=ln(7) is y=7x+7-7ln(7)

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tangent of e^x,\at x=ln(7)

tangent of

e^{x}, at x = ln (7)

y = 7 x + 7 - 7 ln (7)

Solution steps

Find the tangent point:

(ln (7), 7)

Find the slope of

y = e^{x} : \frac{d y}{d x} = e^{x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 7

Find the line with slope m=

7

and passing through

(ln (7), 7) : y = 7 x + 7 - 7 ln (7)

y = 7 x + 7 - 7 ln (7)

tan (e^{3 t}) + e^{t a n (3 t)}

f (x) = 7 e^{x} cos (x)

x \to 2 lim (7 - x)

\int_{1}^{\infty} x^{- \frac{1}{3}} d x

\frac{d}{d t} (- e^{- 4 t} + 4 t e^{- 4 t})

What is the tangent of e^x,\at x=ln(7) ?
The tangent of e^x,\at x=ln(7) is y=7x+7-7ln(7)