What is the solution for y^{''}+y= 3/2 sin(x) ?

The solution for y^{''}+y= 3/2 sin(x) is y=c_{1}cos(x)+c_{2}sin(x)-(3xcos(x))/4

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y^{''}+y= 3/2 sin(x)

y^{^{''}} + y = \frac{3}{2} sin (x)

y = c_{1} cos (x) + c_{2} sin (x) - \frac{3 x cos ( x )}{4}

Solution steps

y^{''} (x) + y = \frac{3}{2} sin (x)

Solve linear ODE:

y = c_{1} cos (x) + c_{2} sin (x) - \frac{3 x cos ( x )}{4}

y = c_{1} cos (x) + c_{2} sin (x) - \frac{3 x cos ( x )}{4}

\frac{x}{3} (2 x + 1)^{3}

(- 2, 5), (6, 2)

\int x + 1 x d x

\int (1 + x^{3})^{7} 3 x^{2} d x

\frac{\partial}{\partial y} (x^{2} e^{x y})

What is the solution for y^{''}+y= 3/2 sin(x) ?
The solution for y^{''}+y= 3/2 sin(x) is y=c_{1}cos(x)+c_{2}sin(x)-(3xcos(x))/4