What is the derivative of 3x^2+12x+6 ?

The derivative of 3x^2+12x+6 is 6x+12

What is the first derivative of 3x^2+12x+6 ?

The first derivative of 3x^2+12x+6 is 6x+12

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\frac{d}{d x} (3 x^{2} + 12 x + 6)

6 x + 12

Solution steps

\frac{d}{d x} (3 x^{2} + 12 x + 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (12 x) + \frac{d}{d x} (6)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (12 x) = 12

\frac{d}{d x} (6) = 0

= 6 x + 12 + 0

Simplify

= 6 x + 12

Y = (x^{\frac{1}{2}}), Y = 6 - x, Y = 0

\int e^{x - 3} d x

e^{x}, e^{- 3 x}, x = ln (4)

\int \frac{x ^{2} - 2}{x} d x

\frac{150000}{( 4 x + 75 ) ^{2}}

What is the derivative of 3x^2+12x+6 ?
The derivative of 3x^2+12x+6 is 6x+12
What is the first derivative of 3x^2+12x+6 ?
The first derivative of 3x^2+12x+6 is 6x+12