What is the integral from 0 to 0.6 of 125x ?

The integral from 0 to 0.6 of 125x is 22.5

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integral from 0 to 0.6 of 125x

\int_{0}^{0.6} 125 x d x

22.5

Solution steps

\int_{0}^{0.6} 125 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 125 \cdot \int_{0}^{0.6} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{0.6}

= 125 [\frac{x ^{2}}{2}]_{0}^{0.6}

Simplify

= 125 [0.5 x^{2}]_{0}^{0.6}

Compute the boundaries:

0.18

= 125 \cdot 0.18

Simplify

= 22.5

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What is the integral from 0 to 0.6 of 125x ?
The integral from 0 to 0.6 of 125x is 22.5