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Popular >

y^'=xe^{-y}

Solution

y^{^{'}} = x e^{- y}

Solution

y = ln (\frac{x ^{2}}{2} + c_{1})

Solution steps

y^{'} (x) = x e^{- y}

Solve separable ODE:

y = ln (\frac{x ^{2}}{2} + c_{1})

y = ln (\frac{x ^{2}}{2} + c_{1})

Graph

Popular Examples

3y^{''}+5y^'-2y=0

3 y^{^{''}} + 5 y^{^{'}} - 2 y = 0

limit as x approaches 8-of ln(8-x)

x \to 8 - lim (ln (8 - x))

limit as x approaches 1 of ln(9x)+e^x

x \to 1 lim (ln (9 x) + e^{x})

integral of (3x-1)^3

\int (3 x - 1)^{3} d x

integral from 0 to infinity of xe^{-x}

\int_{0}^{\infty} x e^{- x} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=xe^{-y} ?
The solution for y^'=xe^{-y} is y=ln((x^2)/2+c_{1})