What is the solution for (x^2-y^2)dx-2xydy=0 ?

The solution for (x^2-y^2)dx-2xydy=0 is y=sqrt((x^2)/3+(c_{1))/x},y=-sqrt((x^2)/3+(c_{1))/x}

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(x^2-y^2)dx-2xydy=0

(x^{2} - y^{2}) d x - 2 x y d y = 0

y = \frac{x ^{2}}{3} + \frac{c _{1}}{x}, y = - \frac{x ^{2}}{3} + \frac{c _{1}}{x}

Solution steps

(x^{2} - y^{2}) d x - 2 x y d y = 0

Solve Bernoulli ODE:

y = \frac{x ^{2}}{3} + \frac{c _{1}}{x}, y = - \frac{x ^{2}}{3} + \frac{c _{1}}{x}

y = \frac{x ^{2}}{3} + \frac{c _{1}}{x}, y = - \frac{x ^{2}}{3} + \frac{c _{1}}{x}

\frac{\partial}{\partial x} ((\frac{x}{y}) e^{x y})

\int 5 x cos (2 x) d x

\frac{d y}{d x}, y = 7 x^{- 4}

\int 2 x cos (2 x) d x

0.4 e^{- 0.4 t}, 0, 4

What is the solution for (x^2-y^2)dx-2xydy=0 ?
The solution for (x^2-y^2)dx-2xydy=0 is y=sqrt((x^2)/3+(c_{1))/x},y=-sqrt((x^2)/3+(c_{1))/x}