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Popular >

x^{''}+2x^'+2=0

Solution

x^{^{''}} + 2 x^{^{'}} + 2 = 0

Solution

x = c_{1} + c_{2} e^{- 2 t} - t

Solution steps

x^{''} (t) + 2 x^{'} (t) + 2 = 0

Solve linear ODE:

x = c_{1} + c_{2} e^{- 2 t} - t

x = c_{1} + c_{2} e^{- 2 t} - t

Graph

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Frequently Asked Questions (FAQ)

What is the solution for x^{''}+2x^'+2=0 ?
The solution for x^{''}+2x^'+2=0 is x=c_{1}+c_{2}e^{-2t}-t