What is the derivative of tan^3(x/4) ?

The derivative of tan^3(x/4) is 3/4 tan^2(x/4)sec^2(x/4)

What is the first derivative of tan^3(x/4) ?

The first derivative of tan^3(x/4) is 3/4 tan^2(x/4)sec^2(x/4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (tan^{3} (\frac{x}{4}))

\frac{3}{4} tan^{2} (\frac{x}{4}) sec^{2} (\frac{x}{4})

Solution steps

\frac{d}{d x} (tan^{3} (\frac{x}{4}))

Apply the chain rule:

3 (tan (\frac{x}{4}))^{2} \frac{d}{d x} (tan (\frac{x}{4}))

= 3 (tan (\frac{x}{4}))^{2} \frac{d}{d x} (tan (\frac{x}{4}))

\frac{d}{d x} (tan (\frac{x}{4})) = sec^{2} (\frac{x}{4}) \frac{1}{4}

= 3 (tan (\frac{x}{4}))^{2} sec^{2} (\frac{x}{4}) \frac{1}{4}

Simplify

3 tan^{2} (\frac{x}{4}) sec^{2} (\frac{x}{4}) \frac{1}{4} : \frac{3}{4} tan^{2} (\frac{x}{4}) sec^{2} (\frac{x}{4})

= \frac{3}{4} tan^{2} (\frac{x}{4}) sec^{2} (\frac{x}{4})

\frac{\partial}{\partial x} (tan (3 + 2 x^{2} y^{4} z^{2}))

\int - x e^{2 x} d x

\int 9 x arcsin (x) d x

\frac{\partial}{\partial x} (e^{y} sin (x))

x \to 0 lim (\frac{∣ x - 3 ∣}{x - 3})

What is the derivative of tan^3(x/4) ?
The derivative of tan^3(x/4) is 3/4 tan^2(x/4)sec^2(x/4)
What is the first derivative of tan^3(x/4) ?
The first derivative of tan^3(x/4) is 3/4 tan^2(x/4)sec^2(x/4)