What is (\partial)/(\partial x)(9x^{4y}) ?

The answer to (\partial)/(\partial x)(9x^{4y}) is 36yx^{4y-1}

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(\partial)/(\partial x)(9x^{4y})

\frac{\partial}{\partial x} (9 x^{4 y})

36 y x^{4 y - 1}

Solution steps

\frac{\partial}{\partial x} (9 x^{4 y})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{\partial}{\partial x} (x^{4 y})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 9 \cdot 4 y x^{4 y - 1}

Simplify

= 36 y x^{4 y - 1}

\frac{2 s + 5}{s ^{2} + s}

\int 34 x + 20 d x

\frac{d}{d y} (ln (\frac{( 3 y + 1 ) ^{4}}{y ^{2} + 1}))

x \to 0 - lim (x^{2} - \frac{1}{x})

f (x) = \frac{x ^{4}}{4}

What is (\partial)/(\partial x)(9x^{4y}) ?
The answer to (\partial)/(\partial x)(9x^{4y}) is 36yx^{4y-1}